a)I√3-√5I+I√3+√5I-I3-2√5I=(-√3+√5)+(√3+√5)-(-3+2√5)=-√3+√5+√3+√5+3-2√5=3 √3-√5 <0 I√3-√5I = -( √3-√5)=-√3+√5 √3+√5 >0 I√3+√5I=+(√3+√5)=√3+√5 3-2√5 <0 I3-2√5I =-(3-2√5) =-3+2√5 b)I2-√5I-I√3+√5I+I1-√3I=(-2+√5)-(√3+√5)+(-1+√3)=-2+√5-√3-√5-1+√3=-3 2-√5 <0 I2-√5I = -(2-√5)=-2+√5 √3+√5 >0 I√3+√5I=+(√3+√5)=√3+√5 1-√3 <0 I1-√3I =-(1-√3) =-1+√3 c)I√3+√2I-I√3+5I-I1-√2I+I-5I=√3+√2-(√3+5)-(-1+√2)+5= =√3+√2-√3-5+1-√2+5=1 √3+√2 >0 I√3+√2I =+(√3+√2)=√3+√2 √3+5 >0 I√3+5I=+(√3+5)=√3+5 1-√2 <0 I1-√2I =-(1-√2) =-1+√2 -5<0 I-5I=-(-5)=5 d)I√2-√3I-I2-√3I+I1-√2I-I-3I=-√2+√3+2-√3+-1+√2+3=4 √2-√3 <0 I√2-√3I =-( √2-√3)=-√2+√3 2-√3 >0 I2-√3I = 2-√3 1-√2 <0 I1-√2I =-(1-√2) =-1+√2 -3<0 I-3I=-(-3)=3
Am nevoie de exercitiul 10,de sus.Macar un subpunct explicat,va rog, ca sa inteleg.Nu stergeti intrebarea!
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2021-01-14 17:42:48
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