Matematică
bichirmariana
2015-10-31 18:40:03
calculati: [1,3la puterea 4 :1,3²:1,3+1,3³la puterea0*(3,1²-3²)*10²]:3,1=
Răspunsuri la întrebare
adrenalina
2015-10-31 19:24:38

[1,3^4:1,3^2:1,3+(1,3^3)^0×(3,1^2-3^2)×10^2]:3,1= [1,3^2:1,3+1×(9,61-9)×100]:3,1= (1,3+0,61×100):3,1= (1,3+61):3,1= 62,3:3,1=20,0967742

giorgiana9925
2015-10-31 19:25:53

[1,3⁴:1,3²:1,3+1,3³la puterea 9×(3,1²-0²)×10²]:3,1= 1,3⁴-(scazi doar la putere)1,3²:1,3+1,3la puterea0×(9,61-9)×10²]:3,1= (1,3²:1,3+1×0,61×100):3,1= (1,3+1,61×100):3,1= (0,31×100):3,1= 31:3,1= 31(×10):3,1(×10)= 310:31= 10 Sper ca te-am ajutat!

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