a + a + 1 + a + 2 = 102 3a = 102 - 3 a = 99 : 3 a = 33 a + 1 = 33 + 1 = 34 a + 2 = 33 + 2 = 35

a+b+c=102 a,b,c=numere.consecutive a,b,c=? a=1segment b=1segment+1 c=1segment+1+1 102-3=99(3segmente.egale) 99:3=33(a) 33+1=34(b) 33+1+1=35(c) Verificare:33+34+35=102 Sper ca te-am ajutat!