Matematică
colfrobert209
2015-11-06 05:05:33
determinați x y si z stiind ca x-y/2=y+z/8=z/6 si x+2z=48
Răspunsuri la întrebare
bragarencoandrei
2015-11-06 08:43:46

x-y/2=y+z/8=z/6 = k x-y/2 = k ==> x-y = 2k y+z/8 =k y+z=8k z/6 =k z= 6k x-y=2k y+z=8k z=6k y+6k =8k y=2k x-y=2k x-2k=2k x=4k x+2z=48 4k+2*6k=48 4k+12k=48 k=3 z=6*3=18 y=2*3=6 x=4*3=12

gemeni94
2015-11-06 08:45:01

[latex] frac{x-y}{2} = frac{y+2}{8} = frac{z}{6} = frac{x-y+y+2+z}{2+8+16} = frac{x+2z}{16} = frac{48}{16} =3[/latex] [latex] frac{z}{6}=3 = extgreater z=18 \ x+2x=48 \ x+2*18=48 \ x+36=48 \ x=12 [latex] frac{x-y}{2} =3 \ 12-y=6 \ y=6[/latex]

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